What is the elution efficiency if 342 mCi of Tc99m are eluted from a generator with 375 mCi on the column?

Prepare for the Radiopharmacy Test. Utilize flashcards and multiple choice questions, complete with hints and detailed explanations. Achieve only the best in your exam!

To determine the elution efficiency, the formula used is:

[ \text{Elution Efficiency} = \left( \frac{\text{Amount Eluted}}{\text{Amount Available}} \right) \times 100 ]

In this case, the amount of Tc-99m eluted is 342 mCi, and the amount available on the column is 375 mCi. Plugging these values into the formula gives:

[ \text{Elution Efficiency} = \left( \frac{342 , \text{mCi}}{375 , \text{mCi}} \right) \times 100 ]

Calculating this:

[ \text{Elution Efficiency} = \left( 0.912 \right) \times 100 = 91.2% ]

This rounds to 91%, which matches the answer choice provided.

Elution efficiency is a critical measurement in radiopharmacy as it indicates how effectively a radioactive isotope can be extracted from a generator. An efficiency of 91% suggests a high level of effectiveness, reflecting that most of the Tc-99m available could be successfully withdrawn for use in medical applications. This assessment is vital for ensuring that sufficient quantities of

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